[erlang-questions] Why is this expression illegal?

[Brujo Benavides]

I believe that inline operators (like bor) are disallowed in binary constructions. See…

1> << 1 bor 16 >>.
* 1: syntax error before: 'bor'
1> << 1 band 16 >>.
* 1: syntax error before: 'band'
1> << (1 band 16) >>.
<<0>>

Brujo Benavides <http://about.me/elbrujohalcon>



> On 18 Jan 2019, at 11:04, Jeroen Koops <koops.j@REDACTED> wrote:
> 
> Hi List!
> 
> If this expressions is legal:
> 
> case A of foo -> 1; bar -> 2 end bor case A of foo -> 8; bar -> 16 end.
> 
> ... and this expression is legal:
> 
> << case A of foo -> 1; bar -> 2 end >>. 
> 
> ... then why is this expression illegal:
> 
> << case A of foo -> 1; bar -> 2 end bor case A of foo -> 8; bar -> 16 end >>.
> 
> (shell responds with "* 1: syntax error before: 'bor'")
> 
> Thanks,
> 
> -- 
> Jeroen Koops
> 
> M: koops.j@REDACTED <mailto:koops.j@REDACTED>
> T: +31-6-55590300
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