A "sleep" command without "receive"
Mon Feb 2 10:14:51 CET 2004
On Mon, 2 Feb 2004 10:27:32 +0100, Corrado Santoro <>
> Hi all,
> I've seen that to wait a timeout the statements I've to use are:
> after T-> ok
> I've also seen that timer:sleep/1 implements the same routine... but...
> I use this timeout in a process that, after the timeout, receives
> something from another process. If the sending process sends data before
> the receiving process calls timer:sleep, the latter function
> returns immediatelly, picking also the message. This is *not* the
> behaviour I want to implement.
> The problem is, obviously, that there is a "receive" statement in
> timer:sleep that "steals" incoming messages.
No, the above receive statement never consumes a message.
My guess is that you have some other receive statement in your
program that picks up the message. Either that, or you have
a rouge version of timer.beam. ;)
> Do you know how to wait a timeout without using "receive"?
There is no way to get a process to sleep without ending up in
a receive somewhere. The above method is safe and the one to use.
If messages get lost in your program, the bug must lie elsewhere.
Ulf Wiger, Senior System Architect
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