[erlang-questions] Why use send_after to send a message is reverse？

[Dao Gui]

talk is cheap, show the code. ^_^

-module(t).
-export([main/0]).
main() ->
                Pid = spawn(fun()->test2() end),
                erlang:send_after(1000,Pid, 1),
                erlang:send_after(1000,Pid,2).
test2() ->

                receive
                                A ->
                                        io:format("dddd:~p~n",[A]),
                                        test2()
                end.

--------------------------------------------------------------------------------------------------------
this output is:
dddd:2
dddd:1

then , I find this in time.c

*    /* insert at head of list at slot */*
*    p->next = tiw[tm];*
*    p->prev = NULL;*
*    if (p->next != NULL)*
* p->next->prev = p;*
*    tiw[tm] = p;*

it insert head when we insert message


*/* Remove from list */*
*remove_timer(p);*
**timeout_tail = p; /* Insert in timeout queue */*
*timeout_tail = &p->next;*

it insert tail when it timeout.

----------------------------------------------------------------------------
Q: but why ? if message timeout, we can insert head. it can keep the order
of message. why don't do this?

other: my English is poor. if something wrong, i hope you forgive me.
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