[erlang-questions] how: Another library flatten function?

Dmitry Belayev rumata-estor@REDACTED
Sat Feb 27 09:34:36 CET 2010


1> lists:map(fun lists:flatten/1,["asd",[["Flow","kalle"]],["Sub","F"]]).
["asd","Flowkalle","SubF"]

It doesn't look like desired
["asd","Flow","kalle","Sub","F"]

Jayson Vantuyl wrote:
>
> Or:
>
> flat(L) -> lists:map(fun lists:flatten/1,L).
>
> Or:
>
> flat(L) -> [ lists:flatten(X) || X <- L ].
>
> Sent from my iPhone
>
> On Feb 26, 2010, at 7:50 AM, Dmitry Belayev <rumata-estor@REDACTED> wrote:
>
>> You can write your own:
>>
>> f(List) ->
>>   lists:reverse(f(List, [])).
>>
>> f([], A) ->
>>   A;
>> f([L|_]=I, A) when is_number(L) ->
>>   [I | A];
>> f([H|Tail], A) ->
>>   f(Tail, f(H, A)).
>>
>> Bengt Kleberg wrote:
>>> Greetings,
>>>
>>> I have the following list: ["asd",[["Flow","kalle"]],["Sub","F"]]
>>> I would like to flatten it to: ["asd","Flow","kalle","Sub","F"]
>>> lists:flatten/1 is too effective. It gives me: "asdFlowkalleSubF"
>>>
>>> Is there another flatten somewhere?
>>>
>>>
>>> bengt
>>>
>>>
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>>
>>
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>
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