[erlang-questions] graphs and trees

French, Mike Mike.French@REDACTED
Thu Dec 20 12:45:47 CET 2007

No, because is_acyclic(G) considers the direction of edges,
and a pair of nodes can be connected by multiple paths that do not form a
What you have found is a Directed Acyclic Graph (DAG).


-----Original Message-----
From: erlang-questions-bounces@REDACTED
[mailto:erlang-questions-bounces@REDACTED]On Behalf Of Richard
Sent: 20 December 2007 11:33
To: mats cronqvist
Cc: erlang-questions@REDACTED
Subject: Re: [erlang-questions] graphs and trees

mats cronqvist wrote:
>   so i've made a directad acyclic graph by calling various functions in
> the digraph module. i theory, the resulting graph should be a tree. is
> there some snazzy graph theory trick to show that the graph is indeed a
> tree?
>   disclaimer; i am by training a physicist, and as such uncomfortable
> with all data structures more complicated than the fixed-size array. so
> no big words please :>

If you get a single component from digraph_utils:components(Graph)
and digraph_utils:is_acyclic(Graph) returns true, you have a tree.


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