[erlang-questions] how do I convert a character to an integer (dict broke the integer I put into it)

Robert Virding rvirding@REDACTED
Sun Dec 16 19:30:05 CET 2007

On 16/12/2007, Dominic Chambers <dominic.chambers@REDACTED> wrote:
> Yes, the following gives me a character instead of a number (I put a
> number in but I got a character out -- which may, as you say, be
> identical anyway):
>   dict:fetch("Key", dict:append("Key", 33, dict:new())).
> but then the problem I get is that if I try to add 1 to that number I
> get a badarith error:
>   dict:fetch("Key", dict:append("Key", 33, dict:new())) + 1.
> I have just made misunderstood what is happening here?

As matthias said dict:append and dict:store are different. Dict:store stores
the value under the key while dict:append appends the new value to a list of
the existing values. If there are no values then the new value is
automatically put in a list. So you get:

1> dict:fetch("Key", dict:store("Key", 33, dict:new())).
2> dict:fetch("Key", dict:append("Key", 33, dict:new())).
3> dict:fetch("Key", dict:append("Key", 35, dict:append("Key", 33,

Dict:fetch (and dict:find) always return the whole value which might be a
list of values or one value.


P.S. Dict:append will also make a list of value which is already there and
not a list. This is probably a mistake, but we were trying to be nice.
Better to be consistent than nice.

P.P.S. Orddict has exactly the same interface but the dictionary is easier
to understand when printed.
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