[erlang-questions] How do funs work ?
Wed Mar 28 19:55:52 CEST 2012
Yes, you are right. But my point is, in this fun, each part of 'fun()
-> something end()' will be executed during F2 is created ?
or that part will be executed when I call F2 like F2() ? I'm not sure
how it works.
I'm also curious about when funs are created at runtime, is there any
difference from hard coded funs? It seems like that I can not extract
abstract code from funs that are created at runtime using
'erlang:fun_info/2'. I'd appreciate if someone could give me a
On Wed, Mar 28, 2012 at 4:01 AM, Hynek Vychodil <hynek@REDACTED> wrote:
> I think it should be
> F2 = fun() -> 9 + 10 +
> fun() -> 7 + 8 +
> fun() -> 5 + 6 +
> fun() -> 3 + 4 +
> fun() -> 1 + 2 +
> fun() -> 0 end()
> On Wed, Mar 28, 2012 at 10:51 AM, Yoshihiro Tanaka <hirotnkg@REDACTED> wrote:
>> I have a function which returns fun as below:
>> make_fun(_, , F) -> F;
>> make_fun(Operator, [Operand1, Operand2|Operands], F) ->
>> F2 = case Operator of
>> plus -> fun() -> Operand1 + Operand2 + F() end;
>> minus -> fun() -> Operand1 - Operand2 + F() end
>> make_fun(Operator, Operands, F2).
>> When I call it as:
>> F1 = make_fun(plus, lists:seq(1,10), fun() -> 0 end).
>> Is F1 same as F2 below ?
>> F2 = fun() -> 1 + 2 +
>> fun() -> 3 + 4 +
>> fun() -> 5 + 6 +
>> fun() -> 7 + 8 +
>> fun() -> 9 + 10 +
>> fun() -> 0 end()
>> Also, is there any difference between funs that are defined at runtime
>> and funs that are defined at compile time in terms of how they are
>> executed ?
>> Thank you
>> erlang-questions mailing list
> Hynek Vychodil
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