[erlang-questions] How do funs work ?

[Hynek Vychodil]

I think it should be

F2 = fun() -> 9 + 10 +
      fun() -> 7 + 8 +
        fun() -> 5 + 6 +
          fun() -> 3 + 4 +
            fun() -> 1 + 2 +
              fun() -> 0 end()
            end()
          end()
        end()
      end()
    end.


On Wed, Mar 28, 2012 at 10:51 AM, Yoshihiro Tanaka <hirotnkg@REDACTED> wrote:
> Hello,
>
> I have a function which returns fun as below:
>
> make_fun(_, [], F) -> F;
> make_fun(Operator, [Operand1, Operand2|Operands], F) ->
>  F2 = case Operator of
>         plus  -> fun() -> Operand1 + Operand2 + F() end;
>         minus -> fun() -> Operand1 - Operand2 + F() end
>       end,
>  make_fun(Operator, Operands, F2).
>
> When I call it as:
> F1 = make_fun(plus, lists:seq(1,10), fun() -> 0 end).
>
> Is F1 same as F2 below ?
> F2 = fun() -> 1 + 2 +
>       fun() -> 3 + 4 +
>         fun() -> 5 + 6 +
>           fun() -> 7 + 8 +
>             fun() -> 9 + 10 +
>               fun() -> 0 end()
>             end()
>           end()
>         end()
>       end()
>     end.
>
>
> Also, is there any difference between funs that are defined at runtime
> and funs that are defined at compile time in terms of how they are
> executed ?
>
> Thank you
> Yoshihiro
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Hynek Vychodil
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