[erlang-questions] Overriding built-in functions in a module
Igor Ribeiro Sucupira
Fri Jun 11 02:34:14 CEST 2010
On Thu, Jun 10, 2010 at 8:58 PM, Richard O'Keefe <> wrote:
> On Jun 10, 2010, at 1:40 AM, Raimo Niskanen wrote:
>> I might argue that since it is a call to an exported function it must be
>> to some *other* function, not the local with the same name.
> Why? Suppose we have a module
Although he didn't say it explicitly, he was talking about your
original code, in which the function bar/1 was not exported.
So, the matter was again the same: the call was to an exported
function, your original bar/1 function was not exported, that makes it
unreachable, we think it's reasonable to call that "unused" and you
don't. There was not much more in the last messages of this
> bar(N) when N > 0 -> ?MODULE:bar(N-1);
> bar(0) -> 'DONG!'.
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