[erlang-questions] how: Another library flatten function?
Fri Feb 26 17:00:21 CET 2010
I personally think this is the best solution, write your own function
that is, as it is such a simple function to start with. Of course, I
wouldn't use reverse but that is just a matter of detail. :-)
On 26 February 2010 16:50, Dmitry Belayev <> wrote:
> You can write your own:
> f(List) ->
> lists:reverse(f(List, )).
> f(, A) ->
> f([L|_]=I, A) when is_number(L) ->
> [I | A];
> f([H|Tail], A) ->
> f(Tail, f(H, A)).
> Bengt Kleberg wrote:
>> I have the following list: ["asd",[["Flow","kalle"]],["Sub","F"]]
>> I would like to flatten it to: ["asd","Flow","kalle","Sub","F"]
>> lists:flatten/1 is too effective. It gives me: "asdFlowkalleSubF"
>> Is there another flatten somewhere?
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>> See http://www.erlang.org/faq.html
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