[erlang-questions] how: Another library flatten function?

Dmitry Belayev <>
Fri Feb 26 16:50:28 CET 2010


You can write your own:

f(List) ->
    lists:reverse(f(List, [])).

f([], A) ->
    A;
f([L|_]=I, A) when is_number(L) ->
    [I | A];
f([H|Tail], A) ->
    f(Tail, f(H, A)).

Bengt Kleberg wrote:
> Greetings,
>
> I have the following list: ["asd",[["Flow","kalle"]],["Sub","F"]]
> I would like to flatten it to: ["asd","Flow","kalle","Sub","F"]
> lists:flatten/1 is too effective. It gives me: "asdFlowkalleSubF"
>
> Is there another flatten somewhere?
>
>
> bengt
>
>
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