[erlang-questions] double to float

Kenneth Lundin <>
Thu Oct 18 19:48:46 CEST 2007


Hi Sten,

I don't understand why you have the code as shown in your example when you can
do it as simple as this:

ac_double(Thefile) ->
        <<Y/float, B/binary>> = Thefile,
        {B,Y}.


/Kenneth Erlang/OTP team at Ericsson

On 10/18/07, Sten Kvamme <> wrote:
> Vlad pointed in the right direction, so it's working now (thanks
> Vlad!). But it still puzzles me that I have to mirror the 8 bytes to
> have erl accepting them as a float. In C I just do like this:
> fread(Xrealp, sizeof(Xreal), 1, fpdxf);
>
> Here's the erlang code snippet:
>
> ac_double(Thefile) ->
>        <<X:8/binary, B/binary>> = Thefile,
>    <<X1,X2,X3,X4,X5,X6,X7,X8>> = X,
>    <<Y/float>> = <<X8,X7,X6,X5,X4,X3,X2,X1>>,
>        {B,Y}.
>
> Here is the whole thing (remember I have just bought the book ;-)
> http://www.kvamme.se/pub/dxf.erl.txt
>
> And here's a small binary dxf file to run on it.
> http://www.kvamme.se/pub/b.dxf
>
> I'm learning fast and it's real fun. I can truly recommend the book.
>
> /Sten Kvamme
>
> On Oct 16, 2007, at 20:43 , Vlad Dumitrescu wrote:
>
> > Hi and welcome,
> >
> > On 10/16/07, Sten Kvamme <> wrote:
> >> I'm reading a binary file with lots of double data types. Have
> >> someone already written some code to convert the double 8 bytes,
> >> <<184,162,71,68,75,65,104,64>> to a float?
> >
> > Do you mean
> >    <<X/float>> = <<184,162,71,68,75,65,104,64>>
> > ?
> >
> > regards,
> > Vlad
>
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