[erlang-questions] double to float
Thu Oct 18 19:18:06 CEST 2007
Vlad pointed in the right direction, so it's working now (thanks
Vlad!). But it still puzzles me that I have to mirror the 8 bytes to
have erl accepting them as a float. In C I just do like this:
fread(Xrealp, sizeof(Xreal), 1, fpdxf);
Here's the erlang code snippet:
<<X:8/binary, B/binary>> = Thefile,
<<X1,X2,X3,X4,X5,X6,X7,X8>> = X,
<<Y/float>> = <<X8,X7,X6,X5,X4,X3,X2,X1>>,
Here is the whole thing (remember I have just bought the book ;-)
And here's a small binary dxf file to run on it.
I'm learning fast and it's real fun. I can truly recommend the book.
On Oct 16, 2007, at 20:43 , Vlad Dumitrescu wrote:
> Hi and welcome,
> On 10/16/07, Sten Kvamme <> wrote:
>> I'm reading a binary file with lots of double data types. Have
>> someone already written some code to convert the double 8 bytes,
>> <<184,162,71,68,75,65,104,64>> to a float?
> Do you mean
> <<X/float>> = <<184,162,71,68,75,65,104,64>>
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