5 List handling
Lists can only be built starting from the end and attaching list elements at the beginning. If you use the ++ operator like this
List1 ++ List2
you will create a new list which is copy of the elements in List1, followed by List2. Looking at how lists:append/1 or ++ would be implemented in plain Erlang, it can be seen clearly that the first list is copied:
append([H|T], Tail) -> [H|append(T, Tail)]; append(, Tail) -> Tail.
So the important thing when recursing and building a list is to make sure that you attach the new elements to the beginning of the list, so that you build a list, and not hundreds or thousands of copies of the growing result list.
Let us first look at how it should not be done:
bad_fib(N) -> bad_fib(N, 0, 1, ). bad_fib(0, _Current, _Next, Fibs) -> Fibs; bad_fib(N, Current, Next, Fibs) -> bad_fib(N - 1, Next, Current + Next, Fibs ++ [Current]).
Here we are not a building a list; in each iteration step we create a new list that is one element longer than the new previous list.
To avoid copying the result in each iteration, we must build the list in reverse order and reverse the list when we are done:
tail_recursive_fib(N) -> tail_recursive_fib(N, 0, 1, ). tail_recursive_fib(0, _Current, _Next, Fibs) -> lists:reverse(Fibs); tail_recursive_fib(N, Current, Next, Fibs) -> tail_recursive_fib(N - 1, Next, Current + Next, [Current|Fibs]).
Lists comprehensions still have a reputation for being slow. They used to be implemented using funs, which used to be slow.
In recent Erlang/OTP releases (including R12B), a list comprehension
[Expr(E) || E <- List]
is basically translated to a local function
'lc^0'([E|Tail], Expr) -> [Expr(E)|'lc^0'(Tail, Expr)]; 'lc^0'(, _Expr) -> .
In R12B, if the result of the list comprehension will obviously not be used, a list will not be constructed. For instance, in this code
[io:put_chars(E) || E <- List], ok.
or in this code
. . . case Var of ... -> [io:put_chars(E) || E <- List]; ... -> end, some_function(...), . . .
the value is neither assigned to a variable, nor passed to another function, nor returned, so there is no need to construct a list and the compiler will simplify the code for the list comprehension to
'lc^0'([E|Tail], Expr) -> Expr(E), 'lc^0'(Tail, Expr); 'lc^0'(, _Expr) -> .
lists:flatten/1 builds an entirely new list. Therefore, it is expensive, and even more expensive than the ++ (which copies its left argument, but not its right argument).
In the following situations, you can easily avoid calling lists:flatten/1:
- When sending data to a port. Ports understand deep lists so there is no reason to flatten the list before sending it to the port.
- When calling BIFs that accept deep lists, such as list_to_binary/1 or iolist_to_binary/1.
- When you know that your list is only one level deep, you can can use lists:append/1.
... port_command(Port, DeepList) ...
... port_command(Port, lists:flatten(DeepList)) ...
A common way to send a zero-terminated string to a port is the following:
... TerminatedStr = String ++ , % String="foo" => [$f, $o, $o, 0] port_command(Port, TerminatedStr) ...
Instead do like this:
... TerminatedStr = [String, 0], % String="foo" => [[$f, $o, $o], 0] port_command(Port, TerminatedStr) ...
> lists:append([, , ]). [1,2,3] >
> lists:flatten([, , ]). [1,2,3] >
In the performance myth chapter, the following myth was exposed: Tail-recursive functions are MUCH faster than recursive functions.
To summarize, in R12B there is usually not much difference between a body-recursive list function and tail-recursive function that reverses the list at the end. Therefore, concentrate on writing beautiful code and forget about the performance of your list functions. In the time-critical parts of your code (and only there), measure before rewriting your code.
Important note: This section talks about lists functions that construct lists. A tail-recursive function that does not construct a list runs in constant space, while the corresponding body-recursive function uses stack space proportional to the length of the list. For instance, a function that sums a list of integers, should not be written like this
recursive_sum([H|T]) -> H+recursive_sum(T); recursive_sum() -> 0.
but like this
sum(L) -> sum(L, 0). sum([H|T], Sum) -> sum(T, Sum + H); sum(, Sum) -> Sum.