[erlang-questions] 回复： How to make a short circuit in erlang ?

[饕餮]

My teammate also say I should try to write more function.
It sounds good!
And I also hear Erlang don't have any way to return immediately.  
I have some idea to refact it now, thanks!


------------------ 原始邮件 ------------------
发件人: "Bob Ippolito"<bob@REDACTED>;
发送时间: 2013年3月26日(星期二) 上午10:54
收件人: "饕餮"<249505968@REDACTED>; 
抄送: "erlang-questions"<erlang-questions@REDACTED>; 
主题: Re: [erlang-questions] How to make a short circuit in erlang ?



There general strategy is to use more functions or have a flat case on a tuple of comparisons (if that can be done sensibly). You could also use exceptions for flow control, but then you have two problems :) 
On Monday, March 25, 2013, 饕餮 <249505968@REDACTED> wrote:
When in other language.We can use like:
 example(Something){
    if( Something == false)
        return;
    //do something here;
}
But in Erlang.I have to write like:
 example(Something) ->
    if
        Something == false ->
             false;
        true ->
            %do something here
     end.




That's could make the multiple nested like:
 example(Something) ->
    if
        Something == false ->
             false;
        true ->
            if
                Otherthing == false ->
                     false
                true ->
                    %do something here
     end.


Some code could make 5 or more nested in it.
 Is there any idea to make short circuit to reduce of the nested?
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