[erlang-questions] Message Loop in Gen_Server
Tim Watson
watson.timothy@REDACTED
Wed Apr 17 21:05:01 CEST 2013
Hi,
When you subscribe, channel messages will be sent to the supplied Pid whenever something happens, e.g., basic.deliver etc.
So you don't need to go into a loop, because you've passed self() which in init/1 is the server's process id. What you do instead is to code your handle_info/2 clauses to deal with the AMQP messages.
You might want to take a look at amqp_gen_consumer as an alternative to gen_server for this as well.
Cheers,
Tim
On 17 Apr 2013, at 18:33, Lee Sylvester <lee.sylvester@REDACTED> wrote:
> Hey guys,
>
> So, I've hit a "best practice" conundrum in OTP; I have a server utilising gen_server for a RabbitMQ consumer. In the init of that gen_server, I'm setting up a RabbitMQ connection, but I also need to start a loop. My guess was that I shouldn't call this before init exits, as I was passing the Connection and Channel objects to state for handling elsewhere. If I handle the loop in init, surely it will never return?
>
> To simplify what I'm saying (as I'm confusing myself here), here's my code:
>
> init([]) ->
> {ok, Connection} = amqp_connection:start(#amqp_params_network{ host="localhost" }),
> {ok, Channel} = amqp_connection:open_channel(Connection),
> amqp_channel:call(Channel, #'exchange.declare'{exchange = <<"user_msgs">>,
> type = <<"direct">>}),
> #'queue.declare_ok'{queue = Queue} =
> amqp_channel:call(Channel, #'queue.declare'{exclusive = true}),
> State = {Channel, Connection},
> amqp_channel:call(Channel, #'queue.bind'{exchange = <<"user_msgs">>,
> routing_key = term_to_binary(node(self())),
> queue = Queue}),
> amqp_channel:subscribe(Channel, #'basic.consume'{queue = Queue,
> no_ack = true}, self()),
> receive
> #'basic.consume_ok'{} -> ok
> end,
> loop(Channel),
> {ok, State}.
>
> Now, if I don't put the loop in my init, then how can I be sure that the loop is called every time the gen_server restarts? Can someone please suggest the "right" way to call the loop in my gen_server?
>
> Thanks loads,
> Lee
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