[erlang-questions] Preallocated binary — save memory

[Max Lapshin]

I've looked at erlc -S bc.erl:

{function, bc, 1, 2}.
  {label,1}.
    {line,[{location,"bc.erl",3}]}.
    {func_info,{atom,bc},{atom,bc},1}.
  {label,2}.
    {allocate_zero,1,1}.
    {line,[{location,"bc.erl",3}]}.
    {gc_bif,bit_size,{f,0},1,[{x,0}],{x,1}}.
    {line,[]}.
    {gc_bif,'div',{f,0},2,[{x,1},{integer,336}],{x,1}}.
    {line,[]}.
    {gc_bif,'*',{f,0},2,[{x,1},{integer,45}],{x,1}}.
    {move,{x,0},{y,0}}.
    {move,{x,1},{x,0}}.
    bs_init_writable.
    {move,{x,0},{x,1}}.
    {move,{y,0},{x,0}}.
    {call_last,2,{f,8},1}.



It is really cool!  Erlang understands that resulting binary will be
exactly 45 * (size(Input) div 42) bytes and preallocates it.
This is a very important reason to use list and binary comprehensions.
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