[erlang-questions] Stripping slashes from a string

[Hynek Vychodil]

Wouldn't be this simple code far faster and simpler (especially
compiled with HiPE):

replace([$\\, $n | T]) -> [$\n, replace(T)];
replace([$\\, $r | T]) -> [$\r, replace(T)];
replace([H | T]) -> [H | replace(T)];
replace([]) -> [].

I'm always curious why people tend to use RE instead of few lines of
very simple code especially in Erlang.

Cheers
  Hynek

On Fri, Apr 27, 2012 at 9:28 AM, Martin Dimitrov <mrtndimitrov@REDACTED> wrote:
> Hi,
>
> What I am trying to achieve is not to convert "\\\\n" to "\\n" but "\\n"
> to [10].
>
> Martin
>
> On 4/27/2012 10:24 AM, Sergei Golovan wrote:
>> On Fri, Apr 27, 2012 at 11:19 AM, Martin Dimitrov
>> <mrtndimitrov@REDACTED> wrote:
>>> With 6 it produces double backslashes making the result equivalent to
>>> the initial text:
>> True, I oversaw that the replacing regexp was incorrect too (also, the
>> string itself).
>>
>> 1> re:replace("\\\\r \\\\n text", "\\\\\\\\(r|n)", "\\\\\\1",
>> [{return,list}, global, unicode]).
>> "\\r \\n text"
>> 2>
>>
>> works fine.
>>
>> Cheers!
>
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