[erlang-questions] How would you do 100 ifs?

[Torben Hoffmann]

I would assume that inifinity is 10,000,000 (that is a pretty big 
number, if it is not enough you can just use X * 10,000,000 as infinity) 
and then I would create a dict and store an index for each number 
between 0 and 10,000,000 based on the index in the list and then look up 
the value for X in the dict.

Something like this:

{_,Lookup} = lists:foldl( fun(Ls,{Index,Dict}) ->
                                         NewDict = lists:foldl( fun(L, 
D) -> dict:store(L,Index,D) end,
                                                                Dict,
                                                                Ls),
                                         {Index+1, NewDict}
                           end,
                          {0, dict:new()},
                          ListOfRanges),
dict:find(X,Lookup).

But bear with me I have not given this much thought let alone pushed 
through the compiler.

Cheers,
Torben


On 15/11/11 14:27 , Max Bourinov wrote:
> Hi guys,
>
> I have a value X which is integer, and I have a list of ranges 
> [0....200),[200....600),[600...1000)....etc....[100000, infinity] 
> (this is just an example). We can assume that the list is static.
>
> I have frequently check the index of the range X belongs to.
> How would you implement it in Erlang?
>
> Best regards,
> Max
>
>
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