[erlang-questions] Float to binary

[Alexey Romanov]

> It seems to
> know that F is 1.0 as it let me rebind it.

1) All variables in list and binary comprehension generators are fresh, so
<<F:64/float>> <= ... does not rebind F at all.

> If I have a float value. This happens to be a frequency in MHz which I
> need to convert to a 32 bit integer big-endian format in Hz how do I get
> the float into a suitable format.

Why do you want to convert it to binary at all, instead of simply
`round(F*1000000)`?

But if you do (e.g. you want to pack multiple floats there),

1> <<1.0:64/float>>.
<<63,240,0,0,0,0,0,0>>


Yours, Alexey Romanov



On Mon, Mar 21, 2011 at 5:09 PM, Bob Cowdery <bob@REDACTED> wrote:
> If I have a float value. This happens to be a frequency in MHz which I
> need to convert to a 32 bit integer big-endian format in Hz how do I get
> the float into a suitable format.  The following converts the term into
> an external term format which is no good for the binary comprehension.
> How can I convert the value into a binary without getting the external
> 1> F=1.0.
> 1.0
> 2> B = term_to_binary(F, [{minor_version, 1}]).
> <<131,70,63,240,0,0,0,0,0,0>>
> 3> << <<(round(F*1000000)):32/big>> || <<F:64/float>> <=
> <<63,240,0,0,0,0,0,0>> >>.
> <<0,15,66,64>>
>
> Thanks once again for any help.
>
> Bob
>
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