[erlang-questions] omaha poker hand permutations

[Vincenzo Maggio]

I don't think is possible because the filter you are willing to apply is valid only after you have all the occurences in the resulting list.

Vincenzo

> From: joelr1@REDACTED
> Date: Tue, 16 Aug 2011 15:27:43 +0100
> To: erlang-questions@REDACTED
> Subject: Re: [erlang-questions] omaha poker hand permutations
> 
> The problem can be reduced to the following:
> 
> 5> L3 = ["AD", "AH", "AS", "QS"].
> ["AD","AH","AS","QS"]
> 
> 6> L4 = [ {A, B} || A <- L3, B <- L3, A /= B].                            
> [{"AD","AH"},
>  {"AD","AS"},
>  {"AD","QS"},
>  {"AH","AD"},
>  {"AH","AS"},
>  {"AH","QS"},
>  {"AS","AD"},
>  {"AS","AH"},
>  {"AS","QS"},
>  {"QS","AD"},
>  {"QS","AH"},
>  {"QS","AS"}]
> 
> Note the duplicate pairs of AD, AH and AH, AD.
> 
> Can these be eliminated inside the list comprehension itself?
> 
> 	Thanks, Joel
> 
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