[erlang-questions] Second order function lists:map

[Rob Charlton]

Hi Franco,

Well you could either swap the function parameters in my first answer 
(paa(L) -> fun(A) ->...) or you could go with Jeroen's solution using 
list comprehensions - which is arguably more elegant.

Calling apply(F,[X]) is equivalent to F(X), but your solution below 
looks fine to me.

Cheers

Rob

Franco Milicchio wrote:
> Rob, what do you think of this solution?
>
> paa(L) ->
>     fun(X) ->
>             lists:map(fun(F)->apply(F, [X]) end, L)
>     end.
>
>
> Thanks for your pointers!
>
>
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-- 
Rob Charlton
Savage Minds Ltd