[erlang-questions] The is_record() guard

[Bjorn Gustavsson]

2009/7/23 Oscar Hellström <oscar@REDACTED>:
> Hi Steve,
>
> You could also do it this way:
>
> transform(#rec_a{} = R) -> ... ;
> transform(#rec_b{} = R) -> ... ;
> ...

Yes, that is the recommended way to do it.

Not only will the matching in the function head be more efficient, but
the compiler
may also generate better code for further record operations in the
body of the function.

/Bjorn

-- 
Björn Gustavsson, Erlang/OTP, Ericsson AB