[erlang-questions] fread() for numbers - beginner question

BranchingFactor branchingfactor@REDACTED
Mon Apr 20 18:02:05 CEST 2009

Thanks for the quick reply,   Robbi.    I was hoping to avoid the try-and-try-again approach b/c it doesn't extend so nicely to scanning multiple items from a string.  Does Erlang provide any way to read what many other programming languages consider to be the printed representation of a number?

--- On Mon, 4/20/09, Robert Raschke <rtrlists@REDACTED> wrote:
From: Robert Raschke <rtrlists@REDACTED>
Subject: Re: [erlang-questions] fread() for numbers - beginner question
To: branchingfactor@REDACTED
Cc: erlang-questions@REDACTED
Date: Monday, April 20, 2009, 6:57 AM

On Mon, Apr 20, 2009 at 10:43 AM, BranchingFactor
<branchingfactor@REDACTED> wrote:
> I'd like to io_lib:fread() a number from a string.  Unfortunately, if
I use
> "~f" for floating point number, then fread rejects numbers that
don't have
> fractional parts:
>> io_lib:fread("~f", "1").
> {error,{fread,float}}
>> io_lib:fread("~f", "1.").
> {error,{fread,float}}
> (I find this very strange, since both 1 and 1. can be represented in a
> floating point number.)
> And if I use "~d" for decimal integers, then fread won't
read past the
> decimal point:
>> io_lib:fread("~d", "1.0").
> {ok,[1],".0"}
> What is the easiest way to scan a number from a string in erlang? 
> it would scan any number in any input format and return an Erlang object
> that satisfied the is_number() predicate.

scan_number(S) ->
    case io_lib:fread("~f", S) of
        {error, _} -> io_lib:fread("~d", S);
        Result -> Result

This doesn't handle 16#ffff and friends though. but you can extend it
according to you needs.

And "1." is not a valid Erlang number.


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