[erlang-questions] How do I compute daytime difference properly?

[Kirill Zaborski]

DateTime tuple (from erlang:localtime/0) has format {{Year, Month,
Day},{Hour, Minute,Second}}.
Not sure what exact meaning has you function (even if we neglect time
part), e.g. what if I subtract 12:00:00 30th of April 2008 from
12:00:00 1st of May 2008? It looks like we'll get 1000.029 but what
are the units? I'd like to get 1 day or 86400 seconds.

On Mon, May 5, 2008 at 10:07 PM, Greg Burri <greg.burri@REDACTED> wrote:
> Hi,
>  Maybe like this :
>
>  delta_date_ms(D1, D2) ->
>    1000000000 * abs(element(1, D1) - element(1, D2)) + 1000 *
>  abs(element(2, D1) - element(2, D2)) + trunc(abs(element(3, D1) -
>  element(3, D2)) / 1000).
>
>
>  /Greg
>
>  On Sat, May 3, 2008 at 9:10 PM, Igor Ribeiro Sucupira <igorrs@REDACTED> wrote:
>  > I think there's no easier way of doing that.
>  >
>  >  2008/5/3 Kirill Zaborski <qrilka@REDACTED>:
>  >
>  >
>  > >
>  >  > Reading calendar module documentation I see the note:
>  >  > "For computing differences between epochs in time, use the functions
>  >  > counting gregorian days or seconds. If epochs are given as local time, they
>  >  > must be converted to universal time, in order to get the correct value of
>  >  > the elapsed time between epochs. Use of the function time_difference/2 is
>  >  > discouraged."
>  >  > But it's not quite clear to me...
>  >  > E.g. I have 2 values LocalTime1 and LocalTime2 which are somewhat like
>  >  > tuples erlang:localtime/0 and need to compute time difference e.g. in
>  >  > seconds. So should I then convert this values to UTC and then use
>  >  > calendar:datetime_to_gregorian_seconds/1 and then do the subtraction?
>  >  >  Or maybe there is some easier way?
>  >  >
>  >  > Best regards,
>  >  > Kirill.
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