Matching elements of records

Fredrik Thulin ft@REDACTED
Wed Oct 27 12:31:29 CEST 2004


In my application, I find that I often pass records to functions and 
want to end up in different instances of the functions depending on 
some element of the record.

I have done this like test2() below does in a number of places, but I 
would want to to reduce length of fun() lines and to avoid problems in 
the emacs-mode indentation (*) with '#' after 'when'.

Considering the following example code (as far as I can tell, both test1
() and test2() accomplishes what I want), is any of them crazy or in 
some way worse than the other?


-record(foo, {one, two}).

test1(Foo=#foo{one=1}) ->
    io:format("in test1 #1: ~p~n", [Foo]),
test1(Foo=#foo{one=2}) ->
    io:format("in test1 #2: ~p~n", [Foo]),

test2(Foo) when is_record(Foo, foo), == 1 ->
    io:format("in test2 #1: ~p~n", [Foo]),
test2(Foo) when is_record(Foo, foo), == 2 ->
    io:format("in test2 #2: ~p~n", [Foo]),

do() ->
    R=#foo{one=2, two=bar},
    io:format("test1 result : ~p~n", [test1(R)]),
    io:format("test2 result : ~p~n", [test2(R)]),

Result :

14> t:do().
in test1 #2: {foo,2,bar}
test1 result : is_two
in test2 #2: {foo,2,bar}
test2 result : is_two


*) Emacs mode (the one distributed with R10B-0) does not align the 
" == 1" with the "is_record(Foo, foo)" if you want to break 
the line :

test2(Foo) when is_record(Foo, foo), == 1 ->

rather than 

test2(Foo) when is_record(Foo, foo), 
       == 1 ->

It works with non-record variables, like :

test2(Foo, Bar) when is_record(Foo, foo), 
                     Bar == 1 ->

More information about the erlang-questions mailing list