Hopefully simple problem
Vance Shipley
vances@REDACTED
Fri Jan 16 22:50:57 CET 2004
Chris,
You can however pass a fun.
Bfun = fun(X,Y) -> X end.
Xfun = fun(X,Y) -> X + Y end.
X = nnet:neuron (0, Bfun, Xfun, []).
-Vance
More information about the erlang-questions
mailing list