spawn without linking?
Tue Apr 20 11:32:36 CEST 2004
> Hi, I'm pretty new to erlang, but one thing that seems to have caused
> me problems in my toys so far is spawning a process without linking.
> When is it a good idea to do such a thing? Every time I've thought it
> was, it just ended up covering up a bug that ended up being difficult
> to track down.
Things that you want to be independent should not be linked together.
If you have two entirely different applications A and B you absolutely
do not want A to be linked to B.
If you have some error logger L then you *do* want L to be linked to A
and L to be linked to B. Errors in A or B should be reported by L.
Links are in the language for error detection purposes. When a process
terminates other processes in the system might need to know about this
so they can do something about the situation.
Suppose X dies - which other processes should be told about this?
Answer: If X evaluates link(Y) then Y will told if X dies (this is symmetric
so Y might evaluate link(X) for the same effect).
spawn_link could *almost* be defined like this:
Pid = spawn(Fun),
But this is not correct (Why? - the process might die *between* the spawn
and the link) - so spawn_link does spawn and link atomically.
If you're new to Erlang I'd use spawn_link - as you build sexier applications
you should think *carefully* about what should happen when things die and try to
stop errors propagating between independent components.
You might like to look at the documentation for erlang:monitor (do > erl -man man erlang)
- this sets up a asymmetric link - which is often very useful.
> SPY My girlfriend asked me which one I like better.
> pub 1024/3CAE01D5 1994/11/03 Dustin Sallings <dustin@REDACTED>
> | Key fingerprint = 87 02 57 08 02 D0 DA D6 C8 0F 3E 65 51 98 D8 BE
> L_______________________ I hope the answer won't upset her. ____________
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