<div dir="ltr"><div>In the doc page you linked:<br>> If the last expression of a function body is a function call,
a <strong>tail recursive</strong> call is done.<br><br></div><div>Compiler will replace call opcode with a tail call (call_last, call_ext_last, apply_last). You can check it with "erl -S test.erl" to see assembly, and in erl console: "l(modulename)." to load the module then "erts_debug:df(modulename)." to create disassembly from BEAM VM memory (it will be a bit different from the erl -S output).<br><br></div><div>See that your calls are replaced with one of: call_last, call_ext_last, apply_last.</div></div><div class="gmail_extra"><br><div class="gmail_quote">2016-10-17 10:58 GMT+02:00 Salikhov Dinislam <span dir="ltr"><<a href="mailto:Dinislam.Salikhov@kaspersky.com" target="_blank">Dinislam.Salikhov@kaspersky.com</a>></span>:<br><blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex">
<div bgcolor="#FFFFFF" text="#000000">
<div class="m_-6524208612865981557moz-text-flowed" style="font-family:-moz-fixed;font-size:12px" lang="x-unicode">Hello.
<br>
<br>
Erlang guarantees tail recursion optimization and states it in the
documentation:
<br>
<a class="m_-6524208612865981557moz-txt-link-freetext" href="http://erlang.org/doc/reference_manual/functions.html#id78464" target="_blank">http://erlang.org/doc/<wbr>reference_manual/functions.<wbr>html#id78464</a>
<br>
<br>
Does erlang guarantee that tail call optimization is done in a
generic case, without recursion?
<br>
Say, we have a function calling a function from another module as
its final statement:
<br>
alpha() ->
<br>
xxx:beta().
<br>
Is it guaranteed that xxx:beta() will use the stack of alpha()
regardless whether recursion is involved.
<br>
I mean whether the language guarantees it rather than virtual
machine may provide such optimization.
<br>
<br>
Thanks in advance,
<br>
Salikhov Dinislam
<br>
</div>
</div>
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