New EEP draft: Pinning operator ^ in patterns
Raimo Niskanen
raimo+erlang-questions@REDACTED
Wed Jan 20 17:27:16 CET 2021
On Wed, Jan 20, 2021 at 04:22:26PM +0100, Kostis Sagonas wrote:
> On 1/20/21 3:42 PM, Raimo Niskanen wrote:
> > I have vague feeling that this has been asked,
> > but since I can not find it:
> >
> > How is nested fun()s handled?
> >
> > foo(Y) ->
> > F = fun (X) ->
> > Y = X + ^Y,
> > FF = fun (Z) ->
> > Z + ^Y
> > end,
> > FF(Y)
> > end,
> > F(Y).
> >
> > Does the innermost Z + ^Y access the outermost Y from foo(Y), or the Y
> > bound in F/1 i.e Y = X + ^Y?
> >
> > Is there a way to choose which of the outer Y:s to refer to from within FF/1?
>
> Raimo: Your question about nested funs is a good one.
>
> However, I thought that ^ was meant to be used in *patterns* (this is
> even in the subject of this sad thread), and I do not see ^ being used
> in patterns in your example.
>
> Am I missing anything?
Nope. I missed that. Felt like something one might want to do.
Let's see if I manage to use patterns instead:
1: foo(Y) ->
2: F = fun (Y) ->
3: FF = fun (Y) ->
4: ^Y = Y - 1
5: end,
6: FF(Y + 1)
7: end,
8: F(Y + 1).
I guess that would produce warnings for shadowing on line 2 and 3.
I guess that ^Y on line 4 refers to the Y bound on line 2.
I guess that warn_unpinned_vars would not produce any warnings.
Can I match against the Y bound on line 1 from within FF/1?
>
> Are you still of the opinion that this, supposedly "pinning operator"
> (which is neither "pinning" anything nor an "operator") makes Erlang
> less confusing a language?
That is what I am trying to find out...
Cheers
/ Raimo
>
> Cheers,
> Kostis
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--
/ Raimo Niskanen, Erlang/OTP, Ericsson AB
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