[erlang-questions] Bug in sets module? Equal sets aren't equal

[lenartlad@REDACTED]

Hello.

What about this:

sets:size(S1) == sets:size(S2) andalso sets:is_subset(S1, S2)

?

This seems rather elegant, at least to me :-)

Note however that I am not sure what the function sets:is_subset/2 returns for two empty sets (I do not have Erlang available at the moment to test it).

HTH,

Ladislav Lenart


______________________________________________________________
> Od: "Alex S." <alex0player@REDACTED>
> Komu: Hugo Mills <hugo@REDACTED>
> Datum: 20.02.2017 15:11
> Předmět: Re: [erlang-questions] Bug in sets module? Equal sets aren't equal
>
> CC: <erlang-questions@REDACTED>
>
>> 20 февр. 2017 г., в 16:58, Hugo Mills <hugo@REDACTED> написал(а):
>> 
>> sets:from_list([[2, 2], [2, -2]]) =:= sets:from_list([[2, -2], [2, 2]]).
>
>The onyl way to compare them for equality would be elementwise anyway, i.e. I'd roll with sets:to_list, it’s about as optimal as it gets.
>
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