[erlang-questions] Illegal Guard?

Theepan <>
Fri Feb 5 13:40:33 CET 2016


Team - Any idea?


60>

60>

60> is_integer(A = 5).

true

61>

61> fun () when is_integer(A = 5) -> ok end.

* 2: illegal guard expression

62>

62>

62>

62> fun () when is_integer(5) -> ok end.

#Fun<erl_eval.20.54118792>

63>

63>

63> fun (A = 5) when is_integer(A) -> ok end.

#Fun<erl_eval.6.54118792>

64>

64>
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