[erlang-questions] create list quesion

[Roelof Wobben]

Roelof Wobben schreef op 27-1-2015 om 15:53:
> Hello,
>
> Oke,
>
> Something like this in pseudo code :
>
> create(0) ->
> print empty array
>
> create(x) ->
>   create_array(x, []) )
>
> create_array(0, array) ->
>  print array
>
> create_array(x, array) ->
>   add the first item to the array and run create_array again
>
> Roelof
>
>
>
>
>
> Loïc Hoguin schreef op 27-1-2015 om 15:17:
>> You can make a local function that takes more arguments and call it.
>>
>> On 01/27/2015 03:15 PM, Roelof Wobben wrote:
>>> Hello,
>>>
>>> I try now to solve a challenge where I must make a list  from a range,
>>>
>>> So for example if I do create(2) the outcome have to be [ 1, 2]
>>>
>>> So i can do
>>>
>>> create(0) ->
>>>    print array
>>>
>>> but as far as I know the list is then not in the scope so I cannot use
>>> it when I do
>>>
>>> create(2) ->
>>>    add the 2 to the array.
>>>
>>> How do I take care that the list is in the scope and still using only
>>> create(number)
>>>
>>> Can anyone give me a tip about it ?
>>>
>>> Roelof
>>>
>>> _______________________________________________
>>> erlang-questions mailing list
>>> erlang-questions@REDACTED
>>> http://erlang.org/mailman/listinfo/erlang-questions
>>
>

I have now this:

-module(create).

-export([create_list/2, create/1]).

create(0) ->
   [];

create(number) ->
   create_list(number, [] ).

create_list(0, [list]) ->
   [list];

create_list(number, [list]) ->
   create_list( number -1, [number | list] ).

but when i do create:create(1) I see this error :

** exception error: no function clause matching create:create(1) (create.erl, line 5) 


which is correct and wierd. Correct because create(0) is not the right one.
Wierd because it has to look at the second clause.

Roelof