[erlang-questions] Reverses Order of Bytes in Binary
Harit Himanshu
harit.subscriptions@REDACTED
Sat Jan 10 20:50:18 CET 2015
Thanks a lot all, that was the only know I knew based on what I found in
documentation, but I learnt lot other ways to do it.
Plus, One thing I learnt is how to measure performance, so Thank you all
for your time and effort
+ Harit
On Sat, Jan 10, 2015 at 5:07 AM, Michael Uvarov <freeakk@REDACTED> wrote:
> there's another way:
>
> reverse(Bin) when is_binary(Bin) ->
>
> S = bit_size(Bin),
>
> <<V:S/integer-little>> = Bin,
>
> <<V:S/integer-big>>.
>
>
>
>
> On January 10, 2015 12:24:54 PM CET, "Сергей Прохоров" <seriy.pr@REDACTED>
> wrote:
>
>> Probably this one will be more effective
>>
>> reverse(Bin) ->
>> reverse(Bin, byte_size(Bin)).
>>
>> reverse(_, 0) -> <<>>;
>> reverse(Bin, Pos) ->
>> <<(binary:at(Bin, Pos - 1)), (reverse(Bin, Pos - 1))/binary >>.
>>
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