[erlang-questions] Order of evaluation of guards

Martin Koroudjiev mrtndimitrov@REDACTED
Mon Jan 5 10:04:07 CET 2015


Hi, thanks. So the "and" (,) is evaluated first and since (,) is not
short circuit  all will be replaced with true/false. And then the "or"
will be evaluated.


On 1/5/2015 10:57 AM, Ivan Uemlianin wrote:
> The last is correct according to your guards: M < 100. Perhaps you could try:
>
>   ... when N > 0, M > 0, N < 100; 
>           N > 0, M > 0, M < 100 -> ...
>
> Happy New Year!
>
> Ivan
>
> --
> festina lente
>
>
>> On 5 Jan 2015, at 08:51, Martin Koroudjiev <mrtndimitrov@REDACTED> wrote:
>>
>> Hello,
>>
>> First of all - Happy New Year!
>>
>> Suppose we have a function that accepts 2 integers and we want to react
>> only when both integers are greater than 0 and one of them is less than 100:
>>
>> I tried:
>> (dilbert@REDACTED)1> F = fun(N, M) when N > 0, M > 0, N < 100; M < 100
>> -> cool; (_, _) -> not_cool end.
>> #Fun<erl_eval.12.106461118>
>> (dilbert@REDACTED)2> F(1,2).
>> cool
>> (dilbert@REDACTED)3> F(1,200).
>> cool
>> (dilbert@REDACTED)4> F(0,200).
>> not_cool
>> (dilbert@REDACTED)5> F(0,50).
>> cool
>>
>> The last is not correct.
>> What is the order of evaluation of the guards? Sadly parentheses are not
>> allowed in guards.
>>
>> Best regards,
>> Martin
>>
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