[erlang-questions] noob namespace question
Thu Dec 13 01:37:59 CET 2012
On 13/12/2012, at 7:14 AM, Rustom Mody wrote:
> I dont understand. Let me try and be more explicit about my concern.
> Let h be a higher-order function of one argument (h/1)
> Now in the call h(foo)
> How does Erlang know whether foo is a function or an atom?
For one thing, function names in Erlang are *NOT* atoms.
They are *PAIRS* <atom>/<arity>. So if you just see an
atom, it cannot possibly be a function (or the name of a
function) because there simply is not enough information
Actually, I told a lie. Function names are
module:name/arity triples. If you are referring to a
function in the same module, you can omit the module:
If you wanted to call h passing it a reference to a local
function named foo with 3 arguments, you would have to write
In Common Lisp,
(h 'foo) the atom FOO
(h foo) value of the variable FOO
(h #'foo) the function FOO
More information about the erlang-questions