[erlang-questions] process will stack overflow after received many message?

Jovi Zhang <>
Fri Sep 16 10:57:36 CEST 2011


On Fri, Sep 16, 2011 at 4:44 PM, Robert Raschke <> wrote:
>
> On Fri, Sep 16, 2011 at 9:38 AM, Jovi Zhang <> wrote:
>>
>> Hi,
>>    I am a newbie of Erlang, here I have a question for receive
>> message in Erlang loop.
>>    Like below Erlang code, when process receive one message, it will
>> invoke loop again,
>>    then it can service like a server, receive message forever.
>>    BUT is possible that process will stack overflow after receive too
>> many message? the process invoke loop again and again.
>>
>>    I saw there have many code write like this in <<Programming Erlang>>
>> book.
>>
>> loop() ->
>>    receive
>>        hello ->
>>            io:format("hello\n"),
>>            loop();
>>        Other ->
>>            io:format("I don't know what is this message, ~p is ~n"
>> ,[Other]),
>>            loop()
>>    end.
>>
>
> No stack overflow, due to tail call optimisation. See also
> http://www.erlang.org/doc/reference_manual/functions.html#id74170
>
> Robby
>

Thanks, but when I test it using escript, the result is like below,
"loop end" printed two times, it means it stacked!

[ Erlang]# cat jovi.erl
#!/usr/bin/env escript

loop() ->
    receive
        one ->
            io:format("one\n"),
            loop();
        two ->
            io:format("two\n")
    end,
    io:format("loop end\n").


main(_) ->
    Pid = spawn(fun() -> loop() end),
    Pid ! one,
    Pid ! two,
    receive
        _Any -> void
    end.


[ Erlang]# ./jovi.erl
one
two
loop end
loop end
^C



More information about the erlang-questions mailing list