[erlang-questions] strange behaviour of gb_trees
Ulf Wiger
ulf.wiger@REDACTED
Sat May 28 20:17:13 CEST 2011
On 28 May 2011, at 00:39, Nico Meyer wrote:
> Try instead
> 1> T = gb_trees:from_orddict( lists:sort(P) ).
To maintain the abstraction, it should be
1> T = gb_trees:from_orddict( orddict:from_list(P) ).
Note that orddicts are not just sorted lists - they are sorted {Key, Value} lists where each key occurs at most once.
Note also:
2> orddict:from_list([{a,1},{a,2}]).
[{a,2}]
3> lists:ukeysort(1,[{a,1},{a,2}]).
[{a,1}]
Again, stick to the abstraction wherever possible, in order to avoid surprises.
BR,
Ulf W
Ulf Wiger, CTO, Erlang Solutions, Ltd.
http://erlang-solutions.com
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