[erlang-questions] is there "return" in Erlang.
Mon Feb 28 15:48:15 CET 2011
On 2011-02-28, at 09:18 AM, Jachym Holecek wrote:
> # Attila Rajmund Nohl 2011-02-28:
> So "special" constructs in Erlang, like 'case' or 'if', are really just
> syntactic sugar on top of lambdas (the strange scoping rule of 'case'
> breaks the most straightforward approach to this, but can still be dealt
> with cleanly).
> I think this is a very powerful property, although as you can see I have
> a bit of a trouble in clearly expressing why is that. ;-)
> Take care,
> -- Jachym
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This is not exactly true. The 'case ... of' expression has special scoping rules that do not fit those of lambdas or functions in general:
1> case 1 of _ -> R = 3 end.
Compare with a fun/lambda:
3> (fun(_) -> D = 3 end)(1).
* 1: variable 'D' is unbound
And the 'if' expression follows the same pattern. Moreover, in a fun, you will 'shadow' the variables in the head, meaning you'll overwrite them if they existed in the current context. A case expression won't -- using the same binding of 'R = 3' as above:
5> case 2 of R -> yay end.
** exception error: no case clause matching 2
From what I heard, the underlying dispatching principle is similar, but yeah. They're not equivalent in how they handle scoping or binding.
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