[erlang-questions] How to convert a binary to a list of 2 byte ints

[Ivan Uemlianin]

Dear Gleb

That is fantastic, thanks!

I had tried it with bitstring comprehensions but to no avail.  Here you 
are using the bitstring generator <= in a list comprehension.  Cool!

Best wishes

Ivan

On 27/05/2010 11:58, Gleb Peregud wrote:
> You can use binary comprehension:
>
> 4>  X =<<18,255,39,255,73,255,90,255,80,255>>.
> <<18,255,39,255,73,255,90,255,80,255>>
> 5>  [ H ||<<H:2/little-signed-integer-unit:8>>  <= X ].
> [-238,-217,-183,-166,-176]
>    

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Ivan A. Uemlianin
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