Bypassing the expression parser

Mathuvathanan Mounasamy <>
Tue Jun 15 08:12:04 CEST 2010

Hi All,

I read this in this link

> The Erlang shell fetches Erlang expressions from the line editor by calling
> io:parse_erl_exprs(Prompt). The first thing we need to do is to change
> this, so that we get a lower-level representation. Luckily,
> io:scan_erl_exprs(Prompt) exists. It allows us to preempt the expression
> parser, and potentially do something different.
> I chose to use the ‘@’ character to break out of the expression parser. For
> one thing, it stands out, and clearly doesn’t belong to any Erlang
> expression. The token scanner expects a full stop to follow, so the shortest
> example of this new mode would be:
> 1> @.
> lists:reverse([1,2,3]).
> @
> [3,2,1]
> 2>
> When a line starting with ‘@’ is detected, the user is given an empty line,
> for further input. Data is then collected until we enter another ‘@’ on an
> empty line.
> By default, we’re still parsing expressions, and the shell will treat this
> just as it would treat a normal multi-line shell command.
> So far, we haven’t gained much, except perhaps freedom from the repeating
> prompt. We can still use e.g. v(1) and e(1) to fetch the value of this
> command, or to repeat it.

But I couldn't understand and achieve this. Can someone please explain how
to do this?


Mathuvathanan Mou.

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