[erlang-questions] Overriding built-in functions in a module

Richard O'Keefe <>
Fri Jun 4 07:18:58 CEST 2010


On Jun 4, 2010, at 3:39 PM, Igor Ribeiro Sucupira wrote:

> On Thu, Jun 3, 2010 at 10:00 PM, Richard O'Keefe <> wrote:
>> 
>> So let's do what the first error message says:
>> 
>> *    4  bar() -> ?MODULE:spawn(fun (X) -> X+1 end).
>> 
>> m% erlc foo.erl
>> ./foo.erl:6: Warning: defining BIF spawn/1
>> ./foo.erl:6: Warning: function spawn/1 is unused
>> 
>> There's an explicit call there, how can it not be used?
> 
> 
> This was a little bit unrelated to the topic. Given that you can't
> call a non-exported function with that syntax, that code is certainly
> not calling the local fun spawn/1, since it's not exported.

Note that I wasn't suggesting that the call should be *allowed*,
only that it is *there*.  There's a big difference between
"there are NO calls to this function" and
"the calls to this function won't be allowed at run time because
 the function is not exported."

In short, I am not quarreling with the decision to report an
error here, only commenting that the error message is extremely
misleading.



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