> This says > for each X1 in L1 { > for each X2 in L2 { > include X1 - X2 in the result > } > } > > ** sub(Xs, Ys) -> [X-Y || X<- Xs&& Y<- Ys] I find this last one (not yet implemented in Erlang) the more natural and expressive solution to the question. -- Jilani KHALDI --------------------- http://www.iiiaugusta.com