> This says
> for each X1 in L1 {
> for each X2 in L2 {
> include X1 - X2 in the result
> }
> }
>
> ** sub(Xs, Ys) -> [X-Y || X<- Xs&& Y<- Ys]
I find this last one (not yet implemented in Erlang) the more natural
and expressive solution to the question.
--
Jilani KHALDI
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