floating point syntax

[Michael Turner]

I guess this has something to do with the fact that a period is also a
terminator in Erlang syntax.  If you allowed "1." as a legal float,
for example, you're permitting this:

  fp1() -> 1..

And with

  f() -> 1.e5;

you need a bit more token lookahead (since "e5" could be seen as the
start of a new function).  My guess, as I say.

-michael turner

On 4/15/2010, "Robert Virding" <rvirding@REDACTED> wrote:

>Yes, it is supposed to be like that, no, it is not a bug. Floats
>consist of both parts before and after the decimal point and an
>optional exponent.
>
>Robert
>
>On 15 April 2010 16:21, Anthony Shipman <als@REDACTED> wrote:
>> The reference manual says "There are two types of numeric literals, integers
>> and floats. Besides the conventional notation,..."
>>
>> But what is the "conventional notation" exactly? I find that this fails:
>> 19> io_lib:fread("~f", "1e+2").
>> {error,{fread,float}}
>>
>> Also
>> 1.e+2 fails
>> 1 ? ? fails
>> 1. ? ?fails
>> 1.0 ? succeeds
>> .1 ? ?fails
>> 0.1 ? succeeds
>> 1.0e+2 succeeds
>>
>> Is it supposed to be like that or is there a bug?
>>
>> --
>> Anthony Shipman ? ? ? ? ? ? ? ? ? ?Mamas don't let your babies
>> als@REDACTED ? ? ? ? ? ? ? ? ? grow up to be outsourced.
>>
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