floating point syntax
Fri Apr 16 18:26:04 CEST 2010
I guess this has something to do with the fact that a period is also a
terminator in Erlang syntax. If you allowed "1." as a legal float,
for example, you're permitting this:
fp1() -> 1..
f() -> 1.e5;
you need a bit more token lookahead (since "e5" could be seen as the
start of a new function). My guess, as I say.
On 4/15/2010, "Robert Virding" <> wrote:
>Yes, it is supposed to be like that, no, it is not a bug. Floats
>consist of both parts before and after the decimal point and an
>On 15 April 2010 16:21, Anthony Shipman <> wrote:
>> The reference manual says "There are two types of numeric literals, integers
>> and floats. Besides the conventional notation,..."
>> But what is the "conventional notation" exactly? I find that this fails:
>> 19> io_lib:fread("~f", "1e+2").
>> 1.e+2 fails
>> 1 ? ? fails
>> 1. ? ?fails
>> 1.0 ? succeeds
>> .1 ? ?fails
>> 0.1 ? succeeds
>> 1.0e+2 succeeds
>> Is it supposed to be like that or is there a bug?
>> Anthony Shipman ? ? ? ? ? ? ? ? ? ?Mamas don't let your babies
>> ? ? ? ? ? ? ? ? ? grow up to be outsourced.
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