Nested for-loops, there has to be a better way to do this
Yves S. Garret
Fri Jul 31 04:00:55 CEST 2009
Yes, that looks like it could work, but I was hoping for something
within one function. Don't take it the wrong way, but loops (to me)
are supposed to be simple and when it involves more than one function,
it just seems like over-kill :-) .
On Jul 29, 2:25 am, wrote:
> Do you mean something like this?
> callback(Numbers) ->
> io:format("~p~n", [Numbers]).
> loop(Callback, Limits) ->
> loop(Limits, lists:duplicate(length(Limits), 1), Callback).
> loop(Limits, Current, Callback) ->
> case increment(Limits, Current) of
> finished ->
> NewCurrent ->
> loop(Limits, NewCurrent, Callback)
> increment(Limits, Current) ->
> increment(Limits, Current, ).
> increment(, , _) ->
> increment([N|Limits], [N|Current], Done) ->
> increment(Limits, Current, [1|Done]);
> increment(_Limits, [N|Current], Done) ->
> Done ++ [N+1|Current].
> 1> loop:loop(fun loop:callback/1, [2,2,2,2,3]).
> > I was playing around with the idea of implementing a nested for-loop
> > like construct (I will concede, they are evil, but at rare times,
> > necessary.) In non-functional programming languages, they are trivial
> > to do. However, this has proved to be one of those simple things that
> > are a pain in the neck for me. The idea was to be able to pass in a
> > list [5, 5, 10] (for example) and go through it all like 3 dimensional
> > array. The below illustration is far from elegant (it's almost 23:00
> > where I live and need to go to work tomorrow early, so no time to come
> > up with something more sane :) ), but is there as an inquisitive
> > exercise. Now, in my opinion, this implementation sucks (first time
> > I've ever gave such a problem a shot in Erlang.)
> > Is there a better way to do this? Anyone would like to demonstrate
> > it?
> > Note: I've tested this code with the lists [2, 4] and [2, 4, 5].
> > Compiled with:
> > Erlang (SMP,ASYNC_THREADS,HIPE) (BEAM) emulator version 5.6.5
> > My code:
> > ======================================
> > -module(loopWrapper).
> > -export([runLoop/1]).
> > runLoop(List) ->
> > [FirstVal | RestList] = List,
> > NextVal = FirstVal - 1,
> > if (length(RestList) > 0) and (FirstVal > 0) ->
> > io:format("~B~n~n", [FirstVal]),
> > runLoop(RestList),
> > io:format("~n~n"),
> > runLoop([NextVal | RestList]);
> > FirstVal > 0 ->
> > io:format("~B", [FirstVal]),
> > runLoop([NextVal]);
> > true ->
> > null
> > end.
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