[erlang-questions] Re: Nested for-loops, there has to be a better way to do this
Mazen Harake
mazen.harake@REDACTED
Tue Aug 4 08:09:53 CEST 2009
Cool! I did the same thing! Look:
f([4,2,1,1]) -> [4,2,1,1,1,1,1,3,2,1,1,1,1,1,2,2,1,1,1,1,1,1,2,1,1,1,1,1].
Passed TC beautifully! ^-^
/M
Zoltan Lajos Kis wrote:
> for(List) ->
> for(List, [], []).
>
> for([], [], Result) ->
> lists:reverse(Result);
>
> for([], [Hd|Stack], Result) ->
> for(Hd, Stack, Result);
>
> for([Hd|List], Stack, Result) ->
> NewStack = case Hd > 1 of
> true -> [[Hd-1|List]|Stack];
> false -> Stack
> end,
> for(List, NewStack, [Hd|Result]).
>
>
>
>> for:for([4,2,1,1]).
>>
> [4,2,1,1,1,1,1,3,2,1,1,1,1,1,2,2,1,1,1,1,1,1,2,1,1,1,1,1]
>
> Passed all TCs :)
>
> Regards,
> Zoltan.
>
>
>
>
>> Not quite.
>>
>> For your input, this should be your output:
>> [4, 2, 1, 1, 1, 1, 1, 3, 2, 1, 1, 1, 1, 1, 2, 2, 1, 1, 1, 1, 1, 1, 2,
>> 1, 1, 1, 1, 1]
>>
>>
>
>
>
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