[erlang-questions] fread() for numbers - beginner question

[Joe Armstrong]

How about using the tokeniser that Erlang uses?

   > erl_scan:string("pi,is,3.14159,\"strings\",1e10,1234").

 {ok,[{atom,1,pi},
     {',',1},
     {atom,1,is},
     {',',1},
     {float,1,3.14159},
     {',',1},
     {string,1,"strings"},
     {',',1},
     {integer,1,1},
     {atom,1,e10},
     {',',1},
     {integer,1,1234}],
    1}

> {ok, [{float,_,F}], _} = erl_scan:string("3.14159").
{ok,[{float,1,3.14159}],1}
> F.
3.14159

etc.

/Joe



On Mon, Apr 20, 2009 at 11:43 AM, BranchingFactor
<branchingfactor@REDACTED> wrote:
> I'd like to io_lib:fread() a number from a string.  Unfortunately, if I use
> "~f" for floating point number, then fread rejects numbers that don't have
> fractional parts:
>
>> io_lib:fread("~f", "1").
> {error,{fread,float}}
>> io_lib:fread("~f", "1.").
> {error,{fread,float}}
>
> (I find this very strange, since both 1 and 1. can be represented in a
> floating point number.)
> And if I use "~d" for decimal integers, then fread won't read past the
> decimal point:
>
>> io_lib:fread("~d", "1.0").
> {ok,[1],".0"}
>
> What is the easiest way to scan a number from a string in erlang?  Ideally
> it would scan any number in any input format and return an Erlang object
> that satisfied the is_number() predicate.
>
> Thank you,
>
> BF
>
>
>
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