[erlang-questions] conditional expressions
Sat Nov 15 22:42:46 CET 2008
You are evaluating these in the shell. In the first case X is bound to aaa,
which means that when you evaluate the second case X is already bound. Which
means that there is no matching clause. If you do:
1> case  of  -> X = aaa; X -> ok end.
2> case bbb of  -> Y = aaa; Y -> ok end.
2008/11/15 damien morton <>
> 1> case  of  -> X = aaa; X -> ok end.
> 2> case bbb of  -> X = aaa; X -> ok end.
> ** exception error: no case clause matching bbb
> am I missing something?
> On Sun, Nov 16, 2008 at 4:42 AM, mats cronqvist <> wrote:
>> strangely, this also works;
>> case foo() of
>>  -> X = bar();
>> X -> ok
>> as long as X is bound in each clause, you're golden.
>> this might qualify as a gotcha.
> erlang-questions mailing list
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