[erlang-questions] conditional expressions
Sat Nov 15 19:37:39 CET 2008
2008/11/15 damien morton <>
> 1> case  of  -> X = aaa; X -> ok end.
> 2> case bbb of  -> X = aaa; X -> ok end.
> ** exception error: no case clause matching bbb
> am I missing something?
Yes, you missed that shell binds X to aaa in previous expression ;-)
But I think, less magic will be
X = case foo() of
 -> bar();
Y -> Y
> On Sun, Nov 16, 2008 at 4:42 AM, mats cronqvist <> wrote:
>> strangely, this also works;
>> case foo() of
>>  -> X = bar();
>> X -> ok
>> as long as X is bound in each clause, you're golden.
>> this might qualify as a gotcha.
> erlang-questions mailing list
--Hynek (Pichi) Vychodil
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