[erlang-questions] conses in erlang?

[not norwegian swede]

can i use conses in erlang?
like in scheme, then i only need one function. is the range func in erlang ood erlang-style or is there a better way to do it?

(define (seq a b)
    (if (< a b)
        (cons a (seq (+ a 1) b))
        '()))

-module(test).
-export([range/2]).
      
range(Start, End) when Start < End, is_integer(Start), is_integer(End) -> 
    seq(Start, End, []).

seq(Start, End, List) ->
    if Start =< End ->
        seq(Start + 1, End, List ++ [Start]);
    true ->
    List
end.



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